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fix: ListObjectsV2 correctly handles repeated folder names in prefixes (#1104)
Co-authored-by: loverustfs <hello@rustfs.com>
This commit is contained in:
@@ -827,7 +827,12 @@ impl ObjectInfo {
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for entry in entries.entries() {
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if entry.is_object() {
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if let Some(delimiter) = &delimiter {
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if let Some(idx) = entry.name.trim_start_matches(prefix).find(delimiter) {
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let remaining = if entry.name.starts_with(prefix) {
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&entry.name[prefix.len()..]
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} else {
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entry.name.as_str()
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};
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if let Some(idx) = remaining.find(delimiter.as_str()) {
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let idx = prefix.len() + idx + delimiter.len();
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if let Some(curr_prefix) = entry.name.get(0..idx) {
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if curr_prefix == prev_prefix {
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@@ -878,7 +883,14 @@ impl ObjectInfo {
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if entry.is_dir() {
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if let Some(delimiter) = &delimiter {
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if let Some(idx) = entry.name.trim_start_matches(prefix).find(delimiter) {
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if let Some(idx) = {
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let remaining = if entry.name.starts_with(prefix) {
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&entry.name[prefix.len()..]
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} else {
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entry.name.as_str()
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};
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remaining.find(delimiter.as_str())
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} {
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let idx = prefix.len() + idx + delimiter.len();
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if let Some(curr_prefix) = entry.name.get(0..idx) {
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if curr_prefix == prev_prefix {
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@@ -914,7 +926,12 @@ impl ObjectInfo {
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for entry in entries.entries() {
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if entry.is_object() {
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if let Some(delimiter) = &delimiter {
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if let Some(idx) = entry.name.trim_start_matches(prefix).find(delimiter) {
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let remaining = if entry.name.starts_with(prefix) {
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&entry.name[prefix.len()..]
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} else {
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entry.name.as_str()
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};
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if let Some(idx) = remaining.find(delimiter.as_str()) {
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let idx = prefix.len() + idx + delimiter.len();
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if let Some(curr_prefix) = entry.name.get(0..idx) {
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if curr_prefix == prev_prefix {
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@@ -951,7 +968,14 @@ impl ObjectInfo {
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if entry.is_dir() {
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if let Some(delimiter) = &delimiter {
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if let Some(idx) = entry.name.trim_start_matches(prefix).find(delimiter) {
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if let Some(idx) = {
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let remaining = if entry.name.starts_with(prefix) {
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&entry.name[prefix.len()..]
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} else {
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entry.name.as_str()
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};
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remaining.find(delimiter.as_str())
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} {
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let idx = prefix.len() + idx + delimiter.len();
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if let Some(curr_prefix) = entry.name.get(0..idx) {
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if curr_prefix == prev_prefix {
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